write (1-i)(2-i)(3-i)/(1+i) in the form of x +iy
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Step-by-step explanation:
(1+2i)
3
=(1)
3
+3(1)
2
(2i)+3(1)(2i)
2
+(2i)
3
=1+6i−12−8i
=−11−2i
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