Question

write 1723.56 in expanded form using exponents

Answer 1

The expanded form using exponents for the given number is 1723.56 = 1×10³ + 7× 10² + 2× 10 + 3× 1+ 5× 10⁻¹ + 6× 10⁻².

Given that,

The number is 1723.56.

We have to find the expanded form using exponents for the given number.

We know that,

What is exponent?

A number's exponent indicates how many times the number has been multiplied by itself. When an exponent is negative, it indicates the number of times the reciprocal of the base must be multiplied.

Take the number 1723.56

1723.56 = 1×10³ + 7× 10² + 2× 10 + 3× 1+ 5× 10⁻¹ + 6× 10⁻²

Therefore, The expanded form using exponents for the given number is 1723.56 = 1×10³ + 7× 10² + 2× 10 + 3× 1+ 5× 10⁻¹ + 6× 10⁻².

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Answer 2

(1×$10^{3}$) + (7×$10^{2}$) + (2×$10^{1}$) + (3×$10^{0}$) + (5×$10^{-1}$) + (6×$10^{-2}$)

• A number's exponent indicates how many times the number has been multiplied by itself. Exponents are necessary since, without them, it is highly challenging to express the product when a number is repeated several times by itself. Exponent-related problems are solved using the rules of exponents or the properties of exponents. These characteristics are regarded as major exponents rules that must be adhered to when solving exponents. How many times we must multiply the reciprocal of the base is indicated by a negative exponent.
• A fractional exponent is one where the exponent of a number is a fraction. Parts of fractional exponents include square roots, cube roots, and nth roots. A number's exponent is referred to as a decimal exponent if it is expressed in decimal form. Any decimal exponent's proper response can be a little tricky to evaluate, thus in these situations, we discover the approximate solution. It is possible to solve decimal exponent problems by first converting the decimal to fraction form.

Here, according to the given information, we are given that,

1723.56

This can be written in an expanded form by expressing each digit in the powers of 10. We get,

(1×$10^{3}$) + (7×$10^{2}$) + (2×$10^{1}$) + (3×$10^{0}$) + (5×$10^{-1}$) + (6×$10^{-2}$)

hence, the expanded form is, (1×$10^{3}$) + (7×$10^{2}$) + (2×$10^{1}$) + (3×$10^{0}$) + (5×$10^{-1}$) + (6×$10^{-2}$) .

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