write 2 log 3 + 3 log 4 + log 2 in single logarithm
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Answered by
1
2log3 + 3log4 + log2
= log3^2 + log4^3 + log2
= log 9*64*2
= log1152
= log3^2 + log4^3 + log2
= log 9*64*2
= log1152
Answered by
2
hello users ...........
//////////////////////////////////////////////////////////////////////////////////////////////////////////////
question:
2 log 3 + 3 log 4 + log 2 = ?
solution :-
we know that :
log mn = log m + log n
and
here,
2 log 3 + 3 log 4 + log 2
= log 3² + 3 log 2² + log 2
=log 9 + 6 log 2 + log 2
= log 9 + 7 log 2
=
=
= log 9 * 128
= log 1152
//////////////////////////////////////////////////////////////////////////////////////////
✪✪hope it helps ✪✪
//////////////////////////////////////////////////////////////////////////////////////////////////////////////
question:
2 log 3 + 3 log 4 + log 2 = ?
solution :-
we know that :
log mn = log m + log n
and
here,
2 log 3 + 3 log 4 + log 2
= log 3² + 3 log 2² + log 2
=log 9 + 6 log 2 + log 2
= log 9 + 7 log 2
=
=
= log 9 * 128
= log 1152
//////////////////////////////////////////////////////////////////////////////////////////
✪✪hope it helps ✪✪
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