Write 2 log 3 + 3 log 5 – 5 log 2 as a single logarithm.
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Answer:
log(1125/32)
Step-by-step explanation:
2log3+3log5-5log2
=log3²+log5³-log2⁵
=log9+log125-log32
=log[9×125/32]=log(1125/32)
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