Question

Write 2 numbers which differ by 3 and whose product is 54

Answer 1

Let the first number be x

Let the second number be (x - 3)

Given, their product = 54


According to the question,

x × (x - 3) = 54

x² - 3x - 54 = 0

x² - 9x + 6x - 54 = 0

x(x - 9) + 6(x - 9) = 0

(x - 9) (x + 6) = 0

x = -9 = 0 or x = 6 = 0

x = 9 or x = -6



1st number => x

=> 9 ✔


2nd number => x - 3

=> 9 - 3

=> 6 ✔

Answer 2

here is your answer OK ☺☺☺☺☺



let the larger number be x and smaller number be y

x - y = 3......... (1)

xy = 54

(x-y)^2 = (x+y)^2 - 4xy

9 = (x+y)^2 - 216

(x+y)^2 = 225

x + y = 15........... (2)

adding (1) and (2),

2x = 18

x = 9

Substituting x=9 in (2)

y= 15 - 9

= 6

the two numbers are 9 and 6.