Write 28 and 32 as the product of their prime factors and then determine their LCM and HCF
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Answered by
16
28 = 2 x 2 x 7
32 = 2 x 2 x 2 x 2 x 2
LCM = 224
HCF = 4
32 = 2 x 2 x 2 x 2 x 2
LCM = 224
HCF = 4
Answered by
5
given that
prime factorization for 28 and 32
28 = 2×2×7
32 = 2×2×2×2×2
LCM = product of the greatest power of each prime factors in the number
28 =2²×7
32 = 2^5
LCM = 2^5 × 7
= 224
GCD = product of the smallest power of the each common factor in the number.
28 = 2²×7
32 = 2^5
GCD = 2²
= 4.
prime factorization for 28 and 32
28 = 2×2×7
32 = 2×2×2×2×2
LCM = product of the greatest power of each prime factors in the number
28 =2²×7
32 = 2^5
LCM = 2^5 × 7
= 224
GCD = product of the smallest power of the each common factor in the number.
28 = 2²×7
32 = 2^5
GCD = 2²
= 4.
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