Question

Write 2log3 + 3log5 – 5log2 as a single logarithm.

Answer 1

hey mate ur ans

Given➡ 2 log3 + 3log5 - 5log 2

Ur ans

1) use power law ..

>>log3^2 + log 5^3 - log 2^5

>>(log 9+ log125)/log32( using quotient law)

>>log (9*125/32)

>>log 35.156

hope it helps
thank you

Answer 2

$\underline{ \large{ \text{Answer}}} : \\ \\ \text{Now, 2log3 + 3log5 - 5log2} \\ = \text{log}({3}^{2}) + \text{log}({5}^{3}) - \text{log}({2}^{5}) \\ = \text{log9 + log125 - log32} \\ = \text{log} \frac{9 \times 25}{32} \\ \lbrack \because \text{loga + logb = log(ab) \& loga - logb = log} \frac{ \text{a}}{ \text{b}} \rbrack \\ = \boxed{\text{log} \frac{225}{32} } \\ \\ \bigstar \: \underline{ \large{ \text{MarkAsBrainliest}}} \: \bigstar$