Math, asked by quantumpatrolz, 3 months ago

Write 3 log 2 + 2 log 7 - 1/2 log 9 as a single algorithm​

Answers

Answered by hakimsarah75
1

Step-by-step explanation:

3 log 2 + 2 log 7 - 1/2 log 9 = log x

log 2^3 + log 7^2 - log 9^1/2 = log x

log 8 + log 49 - log 3 = log x

log (8 + 49 - 3) = log x

log 54 = log x

54 = x

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