Math, asked by honeyangle244, 7 months ago

Write 63 as the product of prime factors. Write the prime factors in ascending order

Answers

Answered by stefangonzalez246
5

Given data: 63

To find: The prime factor in ascending order

Solution:

The prime factor is found by taking LCM of the given number.

Least Common Multiple has the multiple of prime numbers and it should be 1 by the least.

63 => 21 (multiple of 3) => 7 (multiple of 3) => 1 (multiple of 7).

The prime factors of 63 are 3 × 3 × 7.

Hence the prime factor in ascending order is 3 × 3 × 7 or 3^2 × 7.

Answered by amitnrw
1

63 = 3 x 3 x 7   and  3 , 7 are prime factors of 63 in ascending order

"Prime Factorization is finding prime numbers  which when multiplied together results in the original number"

Prime number is a natural number which has only two factors one and number itself.  (e.g. , 2 , 3 , 5 , 7 .... )

Factorize 63

63 = 3 x 21

21  = 3 x 7

=> 63 = 3 x 3 x 7

3 and 7 are prime numbers,

Prime factors of 63 are 3 and 7

Arrange them in ascending order

3 , 7

63 as the product of prime factors  63 = 3 x 3 x 7

Hence,  3 , 7 are prime factors of 63 in ascending order

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