Question

write 7x+3y-4z+k by keeping first and third term in parentheses preceded by minus sign​

Answer 1

Answer:

(i) Given x + y – 3z + y x + y – 3z + y = x + y – (3z – y) (ii) Given 3x – 2y – 5z – 4 3x – 2y – 5z – 4 = 3x – 2y – (5z + 4) (iii) Given 3a – 2b + 4c – 5 3a – 2b + 4c – 5 = 3a – 2b – (–4c + 5) (iv) Given 7a + 3b + 2c + 4 7a + 3b + 2c + 4 = 7a + 3b – (–2c – 4) (v) Given 2a2 – b2 – 3ab + 6 2a2 – b2 – 3ab + 6 = 2a2 – b2 – (3ab – 6) (vi) Given a2 + b2 – c2 + ab – 3ac a2 + b2 – c2 + ab – 3ac = a2 + b2 – c2 – (- ab + 3ac)Read more on Sarthaks.com - https://www.sarthaks.com/683712/place-the-last-two-terms-of-the-following-expressions-in-parentheses-preceded-minus-sign?show=683717#a683717