Write a 2-digit number ab and the number obtained by reversing its digits i.e., ba. Find
their sum. Let the sum be a 3-digit number dad
i.e., ab + ba = dad
(10a + b) + (10b + a) = dad
11(a + b) = dad
The sum a + b can not exceed 18 (Why?).
Is dad a multiple of 11?
Is dad less than 198? Yes
Write all the 3-digit numbers which are multiples of 11 upto 198.
Find the values of a and d.
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little bit hard , pls help me out , I am HAVING same problem.
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