Question

Write a a c++ program to find all Even factor of a number

Answer 1

$\textsf{\large{\underline{Solution}:}}$

The given problem is solved using language - C++.

#include <iostream>

using namespace std;

int main() {

   int n,i;

   cout<<"Enter a number: ";

   cin>>n;

   if(n%2!=0)

       cout<<"Number is odd. There is no even factors.";

   else{

       cout<<"The even factors of the number are: \n";

       for(i=2;i<=n;i+=2){

           if(n%i==0)

               cout<<i<<" ";

       }

   }

   return 0;

}

$\textsf{\large{\underline{Logic}:}}$

• Accept the number from the user.
• If the number is odd, Display message - "No even factors."
• If the number is even - Loop through each even numbers in the range and check if the number is divisible by any even number or not. If true, display it.

See attachment for output.

Answer 2

Answer:

#include <iostream>

using namespace std;

int main()

{

int num;

cout << "Enter a positive number:";

cin >> num;

if(n%2!=0)

cout<<"Number is odd. There is no even factors.";

else{

cout << "Factors of " << num << " are : " << endl;

}

for (int i = 1; i <= num; i++)

{

if (num % i == 0 && i%2==0)

cout << i << "\t";

}

return 0;

}

Explanation:

Hope it helps pls like if you are able to understand this program