write a c program to Take 10 integer inputs from user and store them in an array. Again ask user to give a number. Now, tell user whether that number is present in array or not.
Answers
Answered by
2
Answer:
This program is suitable for turbo c++.
#include<stdio.h>
#include<conio.h>
void main()
{
int n,number;
clrscr();
scanf("%d",&n);
int array[n];
for(int i=0;i<n;i++)
scanf("%d",&array[i]);
printf("Enter the number \n");
scanf("%d",&number);
for(int i=0;i<n;i++)
{
if(number==array[i])
{printf("Yes your number is present\n");
break;
}
getch();
}
Answered by
1
Answer:
#include<iostream>
using namespace std;
int main()
{
int my[3];
for(int i=0;i<3;i++)
cin>>my[i];
for(int i=0;i<3;i++)
cout<<my[i];
cout<<endl;
int n;
cout<<"Enter a number: ";
cin>>n;
for(int i=0;i<n;i++)
{
if(n==my[i])
cout<<"Yes your number is present\n";
}
return 0;
}
Explanation:
Run and execute to check results
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