Question

Write a C++ program wheck whether a given number is greater than 18 or not
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Answer 1

$\huge\bold{AnSwEr}$

$➜syntax \: of \: if \: else \: statement : -$

$if(text \: expression) \\{ \\ statement \: block \\ } \\ else \\ { \\ statement \: block \: 2 \\ }$

$\sf\blue{the \: required \: C++\: program:-}$

#include <iostream>

using namespace std;

int main( )

{

int num;

cout<<"\n enter a number";

cin>>num;

if( num>=18)

{

cout<<"\n Number is greater than 18";

}

else

{

cout<<"\n number is not greater than 18";

}

}

$note : make \: sure \: while \: writting \: programme\\that \: all \: signs \: are \: inserted.\\ \\</p><p>\rm{then \: the \: output \: is ↝\: }$

\rm{enter \: a \: number = 21 \: number \: is \: greater \: than \: 18 \\ enter \: a \: number = 10 \: number \:is \: not \: greater \: than \: 18 }[/tex]

hope this helps..