write a chemical equation of of magnesium sulphite decomposes to form magnesium oxide and Sulphur dioxide
Answers
Answered by
1
2MgSO4 → 2MgO + 2SO2 + O2
HOPE IT HELPS
❤❤✌✌
Answered by
0
Usinglawsofconservationofmass
The laws of conservation of mass states that the total number of atoms of different elements in reactants are equal to the total number of atoms in different elements in products during the chemical reaction.
\bold{\small{\color{green}{Balanced\:Chemical\:Equation:}}}BalancedChemicalEquation:
MgSO_3(s) --^{heat}--> MgO(s) + SO_2(g)MgSO3(s)−−heat−−>MgO(s)+SO2(g)
It is a decomposition reaction.
\bold{\small{\color{green}{Now\:see\:how\:to\:balance:}}}Nowseehowtobalance:
a).Number of Magnesium atoms in left hand side is equal to the number of magnesium atoms in right hand side is 1.
b). Number of Sulphur atoms in left hand side is equal to the number of sulphur atoms in right hand side is 1.
c). Number of oxygen atoms in left hand side is equal to the number of oxygen atoms in right hand side is 3.
The laws of conservation of mass states that the total number of atoms of different elements in reactants are equal to the total number of atoms in different elements in products during the chemical reaction.
\bold{\small{\color{green}{Balanced\:Chemical\:Equation:}}}BalancedChemicalEquation:
MgSO_3(s) --^{heat}--> MgO(s) + SO_2(g)MgSO3(s)−−heat−−>MgO(s)+SO2(g)
It is a decomposition reaction.
\bold{\small{\color{green}{Now\:see\:how\:to\:balance:}}}Nowseehowtobalance:
a).Number of Magnesium atoms in left hand side is equal to the number of magnesium atoms in right hand side is 1.
b). Number of Sulphur atoms in left hand side is equal to the number of sulphur atoms in right hand side is 1.
c). Number of oxygen atoms in left hand side is equal to the number of oxygen atoms in right hand side is 3.
Similar questions