Question

write a chemical equation of the electrolysis of water​

Answer 1

write a chemical equation of the electrolysis of water.

Reduction at cathode:

2 H+(aq) + 2e− → H2(g)

Oxidation at anode:

2 H2O(l) → O2(g) + 4 H+(aq) + 4e.

Answer 2

$H_2O\rightarrow H^++OH^-$

Explanation:

Electrolysis of water is breaking down of water into its constituents that are hydrogen and oxygen by the action of electrical current.  

$H_2O\rightarrow H^++OH^-$

At anode:

$2H_2O(l)\rightarrow O_2(g)+4H^+(aq)+4e^-$

At cathode:

$2H_2O(l)+2e^-\rightarrow H_2(g)+2OH^-(aq)$

Hydrogen cation from anode moves towards the negatively charged electrode that is towards the cathode. On reaching cathode hydrogen cation accepts electrons and get reduced to hydrogen gas through reduction reaction.

Learn more about electrolysis

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