write a cubic polynomial whose roots are 1 , -1,-2
Answers
Answer:
Cubic polynomial = (x - 1)(x + 1)(x + 2)
= (x² - 1)(x + 2)
= x³ + 2x² - x - 2
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The cubic polynomial whose roots are 1 , - 1 , - 2 is x³ + 2x² - x - 2
Given :
The roots of a cubic polynomial 1 , - 1 , - 2
To find :
The cubic polynomial
Solution :
Step 1 of 2 :
Write down the roots
Here it is given that the roots of the cubic polynomial are 1 , - 1 , - 2
Step 2 of 2 :
Find the polynomial
We know that if a , b , c are roots are of a cubic polynomial then the cubic polynomial is
(x - a) (x - b) (x - c) = 0
Hence the required cubic polynomial
= (x - 1)(x + 1)(x + 2)
= (x² - 1²)(x + 2) [ ∵ a² - b² = (a + b) (a - b) ]
= (x² - 1)(x + 2)
= x²(x + 2) - 1(x + 2)
= x³ + 2x² - x - 2
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