write a derivation on vertical motion of two bodies attached to the end of a string that passes over a frictionless pulley. Derevation?
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m1−m2+m/2(m1−m2)g
Force balance equations for two weights can be written as:
T1=m1g−m1a---------(i)
and T2=m2a+m2g----------(ii)
(ii)-(i), we get:
T1−T2=(m1−m2)g−(m1+m2)a------------(iii)
As torque, τ=Iα, we have:
(T1−T2)R=(21MR2).Ra
or, T1−T2=2Ma
Substituting this in equation (iii), we get:
2Ma=(m1−m2
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