write a electroninc configuration of Sn+4 in form of s,p,d,f
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Normal Sn configuration is
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6
5s2 4d10 5p2.
(In filling order. Not removing order of electrons)
Sn 4+ means after removing outermost 4 electrons of 5th shell
Therefore Sn 4+ -- 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 4d10 ( 5s0 5p0)
ankit523039:
you are right
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