Question

write a fraction
i) whose denominator is 3 more than the numerator
ii) whose numerator and denominator add up to 9.

didn't understand the question please help ​

Answer 1

Answer:

7/10

Step-by-step explanation:

Let the numerator = N

Fraction is N/(3+N)

If 5 is added to the numerator

Numerator = 5+N

If 4 is subtracted from denominator

Denominator = 3+N-4 = -1+ N

Combining these

(5+N)/(N-1) = 2…………Equation 1

5+N =2(N-1)

5+N = 2N-2

5+2 = 2N-N

7= N

NUMERATOR = 7

Denominator = 3+N

Denominator = 3+7= 10

Original fraction = 7/10

Answer 2

Answer:

3/6

Step-by-step explanation:

3+6=9

6 is 3 more than 3

Hence, 3/6