Question

Write a Javascript code to print all the odd numbers from 15 backwards to 3

Answer 1

<script type=”text/javascript”>

function printOddNumbers(){

var counter;

for(counter=15;counter<=15;counter=counter-1)

{

if(counter%2!=0)

{

document.write(counter+”<br/>”);

}
may be its help u

}

}

printOddNumbers();

</script>

Answer 2

Below are the program in java script for the above question:

Explanation:

script (this is the tag which is inside the angular tag)//script open tag.

for(var i=15;i>=3;i--) // for loop.  

{

    if(!(i%2==0)) // check for the odd number.

   document.write(i); // print the odd number.

}

script (this is the tag which is inside the angular tag started by '/' symbol)//script closing tag.

Output:

• The output are --

15

13

11

9

7

5

3

Code explanation:

• There is a for loop which runs for the "i" variable whose value starts from the 15 and ends in 3.
• The if condition checks the number is odd or not by dividing it to 2.
• Then the "document.write" statement print the number followed by space.

Learn More:

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