Question

write a number which is less than half of 100 greater than 40, tens digit is 2 greater than the inits digit, sum of digits is 6?​

Answer 1

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Let the One's digit be x

Therefore digit on Ten's place would be x+4

And the Hundred's digit would be x+2

So,

x+(x+4)+(x+2)=12

12=3x+6

3x=6

x=2

Therefore, one's place digit is 2

Ten's place digit is 6

And that of Hundred's place is 4

Thus the number so formed is 462 .

Answer 2

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