Question

Write a pair of integer whose product is -36 and whose diffrence is 15.​

Answer 1

let the integers be x and y

their product is -36

=>>>. XY=-36

difference is 15 x-y=15

so X=15+y

XY=-36

(15+y)y=-36

$y ^{2} + 15y = - 36$

$y ^{2} + 15y + 36 = 0$

$y ^{2} + 12y + 3y + 36 = 0$

$y(y + 12) + 3(y + 12) = 0$

$(y + 12)(y + 3) = 0$

y=-12 and y=-3

if y=-12 then x=15+y=15-12=3

if y=-3 then x=15-3=12 therefore possible values of X.,y are (-12,3),(-3,12)

Answer 2

-12 and 3
-12×3= -36
-12-3= 5
hope it is the answer