Question

rationalise the denominator of √3+1/2√2-√3​

Answer 1

/

$\sqrt{3 } + \frac{1}{2}$

$= \frac{2 \sqrt{3} + 1}{2}$

Answer 2

$\small \bf \pink{hey \: mate \: here \: is \: ur \: ans} \\ \\ \small \bf \pink{ \huge \: solution} \\ \\ \small \bf \pink{ \frac{ \sqrt{3} + 1}{2 \sqrt{2} - \sqrt{3} } } \\ \\ \small \bf \pink{rationalizing \: the \: denominator} \\ \\ \small \bf \pink{ \frac{( \sqrt{3} + 1) (2 \sqrt{2} + \sqrt{3} )}{(2 \sqrt{2} - \sqrt{3}) (2 \sqrt{2} + \sqrt{3} ) } } \\ \\ \small \bf \pink{ \frac{2 \sqrt{6} + 3 + 2 \sqrt{2} + \sqrt{3} }{( {2 \sqrt{2}) }^{2} - ( \sqrt{3} )^{2} } } \\ \\ \small \bf \pink{ \frac{2 \sqrt{6} + 2 \sqrt{2} + 3 + \sqrt{3} }{8 - 3} } \\ \\ \small \bf \pink{ \frac{2 \sqrt{2}( \sqrt{3} + 1) + \sqrt{3} ( \sqrt{3} + 1) }{5} } \\ \\ \small \bf \pink{ \frac{(2 \sqrt{2} + \sqrt{3})( \sqrt{3} + 1) }{5} \: \: \: \: ans }$