write a pair of integer whose productd is -39 whose difference is 16
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Answer:
Let the 2 integers be x and y respectively.
Given:
product = -36 difference = 15
xy = -36.
X - y = 15 x = 15 + y.
.[i]
.[ II ]
putting the value of x in eq. [i]
xy = -36
(15+ y) y = -36
15y + y^2 = -36
y^2 + 15y + 36 = 0
y^2 + 12y + 3y + 36 = 0
y(y + 12 ) + 3y 12 ) = 0
(y + 3) (y + 12) = 0
y=-3, y=-12
y=-3 x = 15+ y = 15 + (-3) = 15 - 3 = 12
y=-12 x= 15+ (-12) x = 15 -12 x=3
The two pair integers are -3 and 12 or 3 and - 12
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