Question

write a pair of integers whose product is -15 and whose diffrence is 8?
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Answer 1

Answer:

Step-by-step explanation:

xy= -15

x-y = 8

x = 8 + y

8y+y² = -15

y² + 8y + 15 = 0

y² + 3y + 5y + 15 = 0

y( y + 3 ) + 5 ( y + 3 ) = 0

( y + 5 )( y + 3 ) = 0

y = -5 , y = -3

If y = -5

then x = -15 ÷ -5 = 3

If y = -3

then x = -15 ÷ -3 = 5

So the pairs can be either 5 and -3

or 3 and -5

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Answer 2

Answer:

-5 and 3 or

3 and -5

Step-by-step explanation:

xy = -15

y = -15/x

x-y=8

x-(-15/x) = 8

x+15/x = 8

(x²+15)/x = 8

x²+15 = 8x

x²+15-8x = 0

x²-8x+15 = 0

x²-5x-3x+15 = 0

x(x-5)-3(x-5) = 0

(x-3)(x-5) = 0

x-3 = 0

x = 3

So, when x =3,

y will be -5

and when x = -3,

y will be 5.

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