Question

write a pair of integers whose product is - 36and whose difference is 15

Answer 1

Answer:

Step-by-step Let a and b bethe 2 nos.

Given a-b=15 and ab=-36

Now from the first equation

= a = 15+b

Putting this value of a in 2nd eq

= ab = -36

=(15+b)b = -36

= b^2 + 15b +36 =0

=b^2 + 12b +3b +36 = 0

= b(b+ 12)+3(b+12) =0

= b is equal to (-12) or (-3)

But since (-12)-(-3) is not equal to 15.

Therefore there are no such pair of integers.