Math, asked by Deepakdalabehera, 1 year ago

write a pair of negative integers whose difference gives 8

Answers

Answered by harshu44
82
Hello Dear!!

Here's your answer...

The pair of negative integers whose difference is 8

-5 and -13
-6 and -14

Verification -

-5-(-13)
-5+13
8

And

-6-(-14)
-6+14
8

____________________

Hope this helps you....

harshu44: Any doubts?? Just comment
Deepakdalabehera: ok
Answered by aquialaska
12

Answer:

Pair of Negative integer whose difference is gives 8 is ( -11 , -19 )

Step-by-step explanation:

Negative Integers : The negative integers are the numbers -1, -2, -3, ... sometimes called the counting numbers or natural numbers, denoted -Z . They are the solution to the simple linear recurrence equation.

Now, We need to find 2 negative integer such that their difference is 8

Let negative integer be x & y

To find a pair, Take x = -11

⇒ -11 - y = 8

⇒ -y = 8 + 11

⇒ -y = 19

y = -19

So, 1st negative integer of pair = -11 & 2nd  negative integer of pair = -19

Here, smaller negative integer should be subtracted from larger negative integer to get positive 8.

Therefore, Pair of Negative integer whose difference is gives 8 is ( -11 , -19 )

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