Question

write a phythagorean triplet whose smallest member is 8

Answer 1

2n = 8

n = 4

n² - 1 = 4² - 1 = 15

n² + 1 =4² + 1 = 17

∴ 8 , 15 , 17.

ok

thnx

Answer 2

Let 2m = 8

So,. M=8/2

M=4

Now ,m^2+1=4^2+1

=16+1

=17

m^2-1=4^2-1

=16-1

=15

So Pythagoras triplet is(8,15,17)