Write a pictogram factor
whose smallest member is 162
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Given 14 is the smallest number in Pythagorean triplet
But we have for every number m>1, we have (2m,m2−1,m2+1) as a Pythagorean triplet
2m=14
m=14/2=7
Then m2=49
m2−1=49−1=48
m2+1=49+1=50
Therefore the Pythagorean triple is =(2m,m2−1,m2+1)=(14,48,50)
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