Question

write a polynomial factor in the blank to complete each statement​

Answer 1

Answer:

1.)p-1

2.)3y

3.)3t²-3t+4

4.)17x

5.)5x²y+3x+2y

Step-by-step explanation:

1.)7p²-7p

Factor out 7p from the expression.

7px(p-1)

2.)18xy+3y

Factor out 3y from expression.

3yx(6x+1)

3.)15t³-15t²+20t

Factor out 5t from the expression.

5tx(3+²-3+4)

4.)17x5-51x⁴-34x

Factor out 17x from the expression.

17x(x⁴-3x³-2)

5.)35x⁵y²+21x⁴y+14x³y²

Factor out 7x³y from the expression

7x³y(5x2+3x+2y

Answer 2

Answer:

As given below

Step-by-step explanation:

The given problem is about finding the factors of the given polynomials

given polynomials   $7p^{2}-7p$

                                $18xy+3y$

                                $15t^{3} -15t^{2} +20t$

                                $17x^{5} -51x^{4} -34x$

                                $35x^{5} y^{2} +21x^{4} y+14x^{3}y^{2}$

1)  $7p^{2} -7p$

⇒ $7p(p-1)$               [take 7p common]

⇒ Factors are $7p$, $(P-1)$  

2) $18xy +3y$  

⇒ $3y(6x+1)$            [ take common 3y ]

⇒ Factors are $3y$ , $(6x+1)$  

3) $15t^{3} -15t^{2} +20t$  

⇒ $5t[3t^{2} -3t+4]$   [ take $5t$ common]

⇒ Factors are $5t$, $(3t^{2} -3t+4)$  

4) $17x^{5} -51x^{4} -34x$    

⇒  $17x [ x^{4} -3x^{3} -2]$   [ take common $17x$ ]

⇒ Factors  are $17x$ , $(x^{4} -3x^{3} -2)$  

5) $35x^{5} y^{2} +21x^{4} y+14x^{3} y^{2}$  

⇒ $7xy[5x^{4}y +3x^{3} +2x^{2} y]$    [ take common $7xy$ ]

⇒Factors are $7xy$, $(5x^{4} y+3x^{3} +2x^{2}y)$