Question

write a polynomial whose roots are 2 and -3

Answer 1

If root is 2, then ( x - 2 = 0 )

If root is -3, then ( x + 3 = 0 )

Therefore,

( x - 2 )( x + 3 ) = 0

${x}^{2} + 3x - 2x - 6 = 0$

${x}^{2} + x - 6 = 0$

Answer 2

sum of roots = $\frac{-b}{a}$

= 2 + (-3) = -1

product of roots = $\frac{c}{a}$

= 2 × (-3) = -6

a = 1

b = 1

c = -6

${ax^2+bx+c=0}$

$\boxed{x^2+x-6 =0}$

$\huge\green{brainlest\:plz}$