Write a program in c++ to calculate the sum of the following seriessum=1/2+2/3+3/4+.........+n/(n+1)
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Answer:
code:
Explanation:
#include <iostream>
using namespace std;
int main()
{
int i, n, sum = 0;
cout << "\n\n Find the sum of the series (1*1) + (2*2) + (3*3) + (4*4) + (5*5) + ... + (n*n):\n";
cout << "------------------------------------------------------------------------------------\n";
cout << " Input the value for nth term: ";
cin >> n;
for (i = 1; i <= n; i++)
{
sum += i * i;
cout << i << "*" << i << " = " << i * i << endl;
}
cout << " The sum of the above series is: " << sum << endl;
}
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