Question

write a program in Java to display the following program​

Answer 1

import java.util.*;

class Term_deposit

{

public static void main (String args[])

{

Scanner in = new Scanner(System.in);

{

System.out.println("enter the sum in term deposit scheme");

int p=in.nextInt();

System.out.println("enter the age of the customer");

int age=in.nextInt();

System.out.println("enter the term");

int t =in.nextInt();

double i = in.nextDouble ;

double amtp = int.nextDouble();

{

if ( age < 60)

{

if

{

if(t<=1)

i = p*7.5*t/100;

if (t <=2)

i = p*8.5*t/100;

if (t <=3)

i=p*9.5*t/100;

if(t < 3)

i=p*10.0*t/100;

}

else

{

if ( t <=1)

i = p*8.0*t/100;

if (t <=2)

i = p*9.0*t/100;

If( t <=3)

i=p*10.0*t/100;

If(t< 3)

i=p*11.0*t/100;

}

amtp= p- i;

System.out.println(/t"Amount deposited"/t"Term"/t"Age"/t"Interest"/t"Amount paid"/t);

System.out.println(/t+p+/t+ t +/t+i+/t+amtp/t");

}}}

Answer 2

Answer:

Num=int(input("Enter the max. lines : ")) # This will collected the number of rows needed to make the patten.  

num=Num+1 # I did this so that we don't need to add one with the old variable always.

for i in range(1,num):  

   for j in range(1,num-i):

       print(end=" ") # This will print the spaces before the numbers in one line.

   for k in range(0,i):

       print(i,end=" ") # This will print the numbers in the pattern in one line.

   print()