Question

write a program in java to print natural numbers from 1 to 50​

Answer 1

Answer:

First, we used the Java For loop to iterate from 1 to maximum value (Here, number = 6).

User entered value: number = 6

For Loop First Iteration: for(i = 1; i <= 6; i++)

Condition is True. So, i Value printed (i.e., 1)

Second Iteration: for(i = 2; 2 <= 6; 2++)

Condition is True. It prints 2

Third Iteration: for(i = 3; 3 <= 6; 3++)

Condition is True. It prints 3

Fourth Iteration: for(i = 4; 4 <= 6; 4++)

Condition is True. 4 printed.

Fifth Iteration: for(i = 5; 5 <= 6; 5++)

Condition is True. It prints 5

Sixth Iteration: for(i = 6; 6 <= 6; 6++)

Condition is True. 6 printed

7th Iteration: for(i = 7; 7 <= 6; 7++)

Condition (7 <= 6) is False. So, the Java compiler exits from the For Loop

Java Program to Print Natural Numbers from 1 to N using While loop

This Java program to return natural numbers from 1 to N is the same as the above example, but we are using the While Loop.

Explanation:

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Answer 2

★$\bf{\underline{Answer::}}$

public class Main {

   public static void main(String [] args) {

       for(int i = 1; i < 50; i++) {

           System.out.println(i);

       }

   }

}

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★$\bf{\underline{Logic::}}$

❖ The program uses a for loop to iterate through numbers 1 to 49, and for each number, it prints the value of the variable i using the System.out.println() method.

❖ The for loop starts with an initialization statement int i = 1, which sets the value of the loop variable i to 1.

❖ The loop then continues as long as the condition i < 50 is true, which means that the loop will iterate 49 times (for i = 1 to i = 49).

❖ During each iteration of the loop, the code inside the loop's block is executed, which simply prints the current value of i to the console.

❖ Therefore, when this program is executed, it will output the numbers 1 to 49 to the console.

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