Question

Write a program that takes 3 numbers as input. If the 3 numbers form a right
angled triangle, print Right Triangle. You can answer in any programming
language like C, C++, Java, Python etc.​

Answer 1

$\texttt{\textsf{\large{\underline{Solution}:}}}$

The given program is written in Java.

import java.util.*;

public class isRightTriangle{

   public static void main(String s[]){

       Scanner sc=new Scanner(System.in);

       int a,b,c;

       System.out.print("Enter length of largest side: ");

       a=sc.nextInt();

       System.out.print("Enter length of base: ");

       b=sc.nextInt();

       System.out.print("Enter length of height: ");

       c=sc.nextInt();

       sc.close();

       if(a * a == b * b + c * c)

           System.out.println("\nIt is a Right angled triangle.");

       else

           System.out.println("\nIt is not a right angled triangle.");

   }

}

$\texttt{\textsf{\large{\underline{Logic}:}}}$

• Accept the sides of the triangle.
• Check if the triangle satisfies pythagoras theorem.
• If true, triangle is a right angled triangle else not.

See the attachment for output.

Answer 2

Answer:

Program:-

import java.util.*;

public class Main

{

public static void main(String args[])

{

Scanner in=new Scanner(System.in);

int a,b,c;

System.out.println("Enter the height of the triangle:");

a=in.nextInt();

System.out.println("Enter the base of the triangle:");

b=in.nextInt();

System.out.println("Enter the hypotenuse of the triangle");

c=in.nextInt(); if(a+b>c&&b+c>a&&c+a>b&&a-b<c&&b-c<a&&c-a<b)

{

System.out.println("Triangle is possible");

if(Math.sqrt(a*a+b*b)==(double)c)

System.out.println("It is a right angled triangle");

else

System.out.println("It is not a right angled triangle");

}

else

System.out.println("Triangle not possible");

}

}

Output is attached.