Question

Write a program to display a
menu for calculating area of
circle or perimeter of circle using
if-else statement.​

Answer 1

Answer:

#include<stdio.h>

#include<conio.h>

void main()

{

int c;

float a,p,r;

printf("\n 1. Area of Circle");

printf("\n 2. Perimeter of Circle");

clrscr();

printf("\n Enter the value of Radius :-");

scanf("%f",&r);

if(c==1)

{

a=3.14*r*r;

printf("\n Area of circle :- %f", a);

}

else

{

p=4*3.14*r;

printf("\n Perimeter of Circle :- %f",p);

}

getch();

}

Answer 2

Here's an example program in Python that displays a menu for calculating the area or perimeter of a circle using if-else statements:

print("Menu:")

print("1. Calculate area of circle")

print("2. Calculate perimeter of circle")

choice = int(input("Enter your choice (1 or 2): "))

if choice == 1:

   radius = float(input("Enter the radius of the circle: "))

   area = 3.14159 * radius ** 2

   print("The area of the circle is", area)

elif choice == 2:

   radius = float(input("Enter the radius of the circle: "))

   perimeter = 2 * 3.14159 * radius

   print("The perimeter of the circle is", perimeter)

else:

   print("Invalid choice!")

• This program first displays a menu with two options: to calculate the area or perimeter of a circle.
• It then prompts the user to enter their choice (1 or 2) and uses an if-else statement to perform the appropriate calculation based on the user's choice.
• If the user enters an invalid choice (i.e., a number other than 1 or 2), the program prints an error message.

#SPJ3