Question

Write a program to find the following series upto n terms:
13,28,43....
Logic is required. No irreverent answer please.

Answer 1

Answer:

import java.util.*;

public class Series

{

public static void main(String args[ ])

{

Scanner in=new Scanner (System. in);

int a=15,b,c,n;

System.out.println("Enter the value of n");

n=in.nextInt();

for(b=1;b<=n;b++)

{

c=(a*b)-2;

System.out.println("The series is ="+c);

}

}

}

Explanation:

In the given series it is the subtractive result of 2 from the multiples of 15.

Such that,

(15×1)-2

=15-2

=13

(15×2)-2

=30-2

=28

(15×3)-2

=45-2

=43

And vice versa.

Answer 2

Answer:

main()

{

int loop_var, n, sum;

printf("\n Enter the number of terms to print:");

scanf("%d",&n);

sum=13;

printf("\n");

for(loop_var=1;loop_var<=n;loop_var++)

{

printf("%d",sum);

sum= sum+15;

}

}

Explanation:

set sun = 13, then with each iteration increase the value by 15 and print the value. The iteration starts at 1 and goes till n so at the end there would be n terms starting with 13.