write a program to find the second largest number of a list of numbers in python
Answers
Answer:
here is a sample that might help you !
Explanation:
# Python program to find second largest
# number in a list
# list of numbers - length of
# list should be at least 2
list1 = [10, 20, 4, 45, 99]
mx=max(list1[0],list1[1])
secondmax=min(list1[0],list1[1])
n =len(list1)
for i in range(2,n):
if list1[i]>mx:
secondmax=mx
mx=list1[i]
elif list1[i]>secondmax and \
mx != list1[i]:
secondmax=list1[i]
print("Second highest number is : ",\
str(secondmax))
Output
Second highest number is : 45
listA= eval(input("Enter list1 :"))
listB = eval(input("Enter list2 :"))
len1 = len(lista)
len2 = len(listB)
for a in range (len1) :
ele = listA[a]
if ele in listB :
print("Overlapped")
break
#loop ends normally, not because of break
else :
print("Separated")
Solution.