Write a program to generate the first 'n' terms of the following series 121, 225, 361,...
Answers
Answered by
19
Answer:
#include<iostream>
int main ()
{
int n, a=11, x=4, i=0, num;
std::cin>>n;
for(i=0;i<n;i++)
{
num=a*a;
std::cout<<num<<" ";
a=a+4;
}
}
Answered by
0
Answer:
The following Python code will solve the above problem. Just copy and paste the code into any python IDE:
n = int(input())
start = 11
while(n!=0):
print(start**2, end=",")
start +=2
n-=1
Explanation:
- First, we take the n terms as input from the user.
- we create a start variable with a value of 11.
- The logic of the series is to print the square of odd numbers starting from 11.
- Like square of 11 = 121
- square of 15 = 225
- square of 19 = 191
- Then we start a loop to iterate n number of times.
- ** operator will calculate the square for us without using any math library function.
- the start is incremented by 2 to reach the next odd number
- n is decremented by 1 so that we move to the termination condition of the loop.
#SPJ2
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