Math, asked by tumhoa01, 9 months ago

write a program to initialize 3,5,7 to the integer variables a,b,c.calculate and print the result of the following expression x=-b+underroot b*b-4ac/2a

Answers

Answered by nitinsultania
0

Step-by-step explanation:

PROGRAM QuadraticEquation

IMPLICIT NONE

REAL :: a, b, c

REAL :: d

REAL :: root1, root2

! read in the coefficients a, b and c

READ(*,*) a, b, c

WRITE(*,*) 'a = ', a

WRITE(*,*) 'b = ', b

WRITE(*,*) 'c = ', c

WRITE(*,*)

! compute the square root of discriminant d

d = b*b - 4.0*a*c

IF (d >= 0.0) THEN ! is it solvable?

d = SQRT(d)

root1 = (-b + d)/(2.0*a) ! first root

root2 = (-b - d)/(2.0*a) ! second root

WRITE(*,*) 'Roots are ', root1, ' and ', root2

ELSE ! complex roots

WRITE(*,*) 'There is no real roots!'

WRITE(*,*) 'Discriminant = ', d

END IF

END PROGRAM QuadraticEquation

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