Write a program to input two unequal positive numbers and check whether
they are perfect square numbers or not. If the user enters a negative number
than the program displays the message 'Square root of a negative number
can't be determined
Sample input: 81,100
sample output:they are perfect square number
sample input :225,99
sample output:225 is a perfect square number
99 is not a prefect square number
Answers
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Explanation:A number is known as a square number or perfect square if the number is a square of another number. That is an number n is square if it can be expressed as n = a * a where a is an integer. Some examples of perfect numbers (square numbers) are ,
9 = 3 * 3, 25 = 5 * 5, 100 = 10 * 10
An interesting property of square number is that it can only end with 0, 1, 4, 6, 9 or 25.
Java Program to Find Whether a Number is a Perfect Square Number
The following Java program checks whether a given number is a perfect square number or not. We take the square root of the passed in number and then convert it into an integer. Then we take a square of the value to see whether it is same as the number given. If they are same, we got a perfect square number!
// Finding whether a number is a perfect square number in Java
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
public class PerfectSquareNumber {
public static void main(String[] args) throws IOException{
BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
System.out.print("Please enter an integer : ");
int number = Integer.parseInt(reader.readLine());
int sqrt = (int) Math.sqrt(number);
if(sqrt*sqrt == number) {
System.out.println(number+" is a perfect square number!");
}else {
System.out.println(number+" is NOT a perfect square number!");
}
}
}
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