Write a program where the user enters a positive integer and the program keeps displaying increasing even numbers until an even number is equal to, or greater than, the number that was entered. The program then displays the sum of the even numbers that were displayed.
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If number contains even digits even number of time Odd digits ... Input : 22233 Output : NO count_even_digits = 3 ... C++ program to count ... int countEvenOdd( int n).
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