write a Pythagorean triple whose one member is 18
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18,80,82are required Pythagorean triplets
daksh123468:
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You have not explained!!! why???
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formula is ( 2m ,m^2-1,m^+1)
2m=18
m=18/2
m=9
so ,2m=9×2=18
m^2-1=9^2-1= 81-1 = 80
m^2+1= 9^2+1= 81+1= 82
2m=18
m=18/2
m=9
so ,2m=9×2=18
m^2-1=9^2-1= 81-1 = 80
m^2+1= 9^2+1= 81+1= 82
Thank you for explaining this!!!
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