Question

Write a Pythagorean triplet if one no. Is 14.

Answer 1

if one member = 14

pythagorean triplet = 2m,m^2 - 1, m^2 + 1

2m= 14

m= 7

m^2-1=7^2-1

49-1=48

m^2+1=7^2+1

49+1=50

pythagoren triplet is 14(given),48,50

Answer 2

2m=14
m=14/2=7
${m}^{2} - 1 = 7 {}^{2} - 1 = 48 \\ {m }^{2} + 1 = 50$
Hope it helps you