write a Pythagorean triplet in which one number is 8
khushitaori99:
6,8,10
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Let 2m=8
m= 8/2=4
m^2-1 = 4^2-1=16-1=15
m^2+1 = 4^2+1=16+1 =17
Hence the Pythagoraen triplet is 8,15 and 17
m= 8/2=4
m^2-1 = 4^2-1=16-1=15
m^2+1 = 4^2+1=16+1 =17
Hence the Pythagoraen triplet is 8,15 and 17
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