Question

write a Pythagorean triplet of 8

Answer 1

Pythagorean triplet is
2m, m^2+1, m^2-1
Let m^2-1 = 8
= m^2= 9
= m= 3
Now,

m^2+1 = 3^2+1
= 9+1= 10

2m= 2×3
= 6

Therefore the Pythagorean triplet is

10,8,6

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Answer 2

hey here is your answer

Pythagorean triplet of 8
pithagorean triplet = (m^2+1) , (m^2 -1) and 2m

let m^2 -1 be 8
m^2 - 1 = 8. -(1)
m^2 = 8+1 = 9
m= √9 = 3

putting 3 in second pithagorean triplet

2m
= 2× 3 = 6.
2m = 6. -(2)

putting 3 in third pithagorean triplet

m^2 + 1
= (3)^2 + 1
= 9 + 1 = 10
m^2 + 1 = 10. -(3)

triplet is 6,8 and 10

another triplet -----

let 2m be 8
2m = 8. -(1)
m = 8/2= 4

putting 4 in second pithagorean triplet

m^2-1
= (4)^2 -1
= 16-1
= 15
m^2 - 1 = 15. -(2)

putting 4 in third pithagorean triplet

m^2 + 1
= (4)^2 +1
= 16+1
= 17
m^2 +1 = 17. -(3)

pithagorean triplet is 8,15 and 17

hope this helps you