write a Pythagorean triplet whose on number is 8
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Answered by
11
Hey
Here is your answer,
Pythagoras triplets are of the form.
2m, m² -1 and m² + 1.
It is given that smallest number is 8.
So, 2m = 8.
m = 4.
Now, second number = m² -1 = 4² - 1 = 15.
and, third number = m² + 1 = 4² + 1 = 17.
Hence, the triplet is 8, 15 and 17.
Hope it helps you!
mark brainliest plzz...
Here is your answer,
Pythagoras triplets are of the form.
2m, m² -1 and m² + 1.
It is given that smallest number is 8.
So, 2m = 8.
m = 4.
Now, second number = m² -1 = 4² - 1 = 15.
and, third number = m² + 1 = 4² + 1 = 17.
Hence, the triplet is 8, 15 and 17.
Hope it helps you!
mark brainliest plzz...
Answered by
0
Answer:
8,15,17
Step-by-step explanation:
2m=8
m=8/2 = 4
m (square)= 4 (square) - 1 = 15
m (square) = 4 (square) + 1 = 17
therefore, the Pythagorean triplets are 8,15 and 17
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