Question

write a Pythagorean triplet whose one member is 16​

Answer 1

Step-by-step explanation:

16, 63,65

n=6(2n=16)

$n {}^{2} - 1 = 63 \\ n {}^{2} + 1 = 65$

Answer 2

Step-by-step explanation:

let 1 member of the pythagorian triplet is 16

We know that the formula of pythagorean triplet is

(2m,m²-1,m²+1)

Let's assume 16=2m(You can take any of them

2m=16

m=16/2

m=8

So the no's are

2m=2×8=16

m²-1=8²-1 =64-1=63

m²-1=63

m²+1=8²+1=64+1=65

m²+1=65

Therefore pythagorean triplet are 16,63,65