Math, asked by usha31310, 6 months ago

write a Pythagorean triplet whose one member is 8​

Answers

Answered by shreyasinha28
2

Answer:

Triplets=8,15,17 is the answer

Answered by piyushsaini552
2

Answer:

Triplets=8,15,17.

Step-by-step explanation:

8

2

=64

⇒ 100−64=36

36

=6

100

=10

Let

Hypotenuse =10 [ Since its greater than 6 and 8 ]

Base =8 and

Perpendicular =6

(Hypotenuse)

2

=(Perpendicular)

2

+(Base)

2

[ Pythagoras theorem ]

⇒ (10)

2

=(6)

2

+(8)

2

⇒ 100=36+64

⇒ 100=100

∴ Pythagorean triplet are 6,8,10

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